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六年级脱式计算

来源:九壹网
一、脱式计算。

123494555 + × × - × ( - )63721256612×36

1851966 ×( - ) (13+ )× ×33612+66

13

5356 ×57 +

215 ÷4

5

83 ×(1883 -21 ×16 ) +34 ×57

13 +47 +23 +17 1

7

647 ×48 1

17

1623÷7+63÷73512034 41355447 9135517 +17 ×16 910 ×11-910 45 ×38 ×59 10117 ×34×7×217 5614723161365 ×215 57 ×14

×1

7 -2325 ×1617 +1625 ×

143598 (1269 +71 )×

23+

25 7183115515

× - ÷ ×错误!未指定书签。 + × 1546246644

32.6× +32.6×0.2

5

512463131 × + ÷6 465× × + 767×14

1257 -(17 +2 ) [1-(58+1

8

×42 45 ×47 ×54 -13 2.5÷4

4104105353 96(9.6×4)

2.08×(9.6÷2.4)÷4.8 780.25×4

5712×325×14 89÷58 115455÷7+55×7 ÷521×3 (81155)32.6×1.9

17.64÷4.9+6.73 3.412.5×3.2

45379+759 46414 +38 )]÷14 59 ×6+49 ÷1

6 -3.2×0.5+0.4 9.6×0.69+1.2×6.9+6.9 0.7871359÷2÷36 (13+1315)÷13 [1(12124)]3÷[(1.2+0.5)×5] 0.25(17-12)14 84818 ×180÷÷÷35×

587×

92.6×1.9÷

×1115(3 1) 128789 2.65×1.7+1.35×1.7 23.4÷887.8-2.1

0.75×18÷0.15 2.5×3.2×1.25 2842÷

14+74×3

413412 +-+ 5.2-11÷7-×3 4÷1+

37575736×

5336325×4÷4× ÷[(-)÷] 445436111111+++++ 2481632 7.6×÷[1.9-1.9×(1.9-1.9)] (5 -1.8)÷[(1.15+

132 )×1 ] 203

32 14 -6.46-3.54 4.2÷1.5-1.5×0.6 (0.92+ )

17257÷(4-2 )

9

53322 (4 -3 )÷( + ) 51.6÷[(3 -

64147541.25)× ] 5

19.98×37-199.8×1.9+1998×0.82 9999×7+1111×37

23111 (70+)× 8.89×36+8.89×232696863+8.89

1200511-1÷2-1÷3- 2007× 216×62006311 ( -

3241225

231÷231

2133×20% (+)×3+

15125503713114×[-(-)] 24×(-)÷ 4.85×0.17+0.48594164865×8.3

234511+×99+ 2-2.86×(6.25-6) 54.2- +

914714641.65÷5+1.29×0.2+

4.8-16

9

0.7÷[(56 -1

4 )×24] 1.4712.5÷25÷0.8÷4

78÷9×35÷3572 15-45÷49

21125×15+5÷154 [((415÷4-10) 7.28-(1.25+0.28) 999012.5×2.5

15 ÷[(2113 +5 )×13 ] 490.85)÷2.5 (1÷227+7÷1)÷5.1 +2.73×35

[1-(1315+10)]÷8 56(114+6) 12÷[2113×(6+3)] [(2153)÷56]

4.85-549 +5.15-9 (

115+217 )×17 ÷(2-1.02)+0.61×14 2000÷

23+(425135-3)×3 (15+49)×41695-4)×11]÷20 (112+4)÷×200.8+1×2008 0.8×4×23×0.6+0.6÷314 33.02-(148.4-1.6×53438+3.6÷4)×29×7.27

5×(453537+8-4) (6-4)÷

21353+3×4 11×

113 +1213 ×(52 -1

3 ) 5×

(341366417 ÷[( +)× ]  - ×454777531521

( + ) 39

11466 10.2-(1.25 + 2.5)÷1.5 1 ÷( + 2.5× ) -

23 + 1

9

1116 ×40-916 ÷1

40

124)]×3

(2-3854×

15)÷52 18)×12.5 519+6×13 140 1920×17-35÷7 8.24537÷4 118(142.545) 6.75116+3)] 25336438 (11213918)×36 11928÷[10-(15+4)] 19263855511 845 34×(

117+113)×13 72÷[(76-23)×3] (831115÷[(12+20)×6] -2.4÷2.5÷0.4 2-1156+3.25-26

516871411 1233525 77[1-(

12-

×459+9÷

(5128+4-5)

-1516÷

12÷[23×

721151710 38524635 12 ÷ 54 ×

×( ÷ (

2 3

33575453 ×4÷ ×4 + ÷ ÷ 8881283847

10(413111-3)×(4-2) 17×[(1+1.5)÷1] 210334133.3[383(10.15)]

54211215733524×+÷ ÷9×÷ +(-5155485723525)× 334169114113[(-)×]÷ (+)÷(÷4-) (+)×54112024510154915-45÷49

111111111 ++++++++ 2612203042567290191256131 ×(+)+0.8 11÷〔×(+)〕 ÷ [ ×

202246561124

( + )] 55

832373485 [()] (1) ×

11941684515215[()÷]

536 ×(÷

56292455+ ) 51.6÷[(3 -1.25)× ] 556627213

)÷(4-2 ) (5 -1.8)÷[(1.15+ )259520

(0.92+2

×1 ] 3(

4177112 + )÷ + [1-( - )]× 3.64×[1÷54310243

1

(2 -2.09)] 10 (2

5573113817 +1 +2 +3. 375)× + ÷ + ( +0.2)× 1281220984938

÷(3—0.5) 71122240.24-20.875 25.4313 5735

25(1563310) (

215538535+3)÷6×11 8×〔9÷(6-4)〕 +120)×1] (13653+4)×24 0.5+6×(0.15+920) 45×3.8+5.2×80%+0.8 (34-23)×12÷0.1 111×3

+

3×5

+

15×7

+

+

1

17×19

111112233445+156

11×2×3 +12×3×4 +13×4×5 +……+1

48×49×50

二、解方程。

28139 X×(1-4 )=3.6 -415 X=10 34 ×(X-13 )=0 5X-3×1077 =5 513

339315÷[(

12+

1

19×21

12

-23 X= 119 5×(X- )=2 

34321421

155123χ×(1+ )=250 χ- χ=0.3 χ

4+14 χ=19

5

χ×(1-114 -5 )=550 10X=

1120 X×133×5=4 Xχ=9.5

3.2×4+50x=112.8 0.3x2.4x=7

5×1.3-2x=5.5 5x1.2)=2.1

3.2×4+50x=112.8 0.3x2.4x=7

5×1.3-2x=5.5 0.8х=41.6

34χ+516χ-6=3 11.3=9.9

4×(x-0.8)=8 2=18

x-0.15x=8.5 0.81

3

x=15 16x-6.4x=36 5×X=825 33×315=18×4 -0.8×60=72 5.9x-2+1.8=3.6 7-0.8×60=725.9 x×(7.2+х)=7.92 6.2-23=35 414 ÷x=2

3

(6+3x)×(x-0.4)=8 x15x310 7÷

113χ+

6-

(x--х--7×

÷

1

2

x +

x-35 x

1=3 5 1-

33 =54

xx3.9 7615x417

8

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