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六年级脱式计算

来源:九壹网
一、脱式计算。

123494555

+ × × - × ( - )×36

637

1853 ×(3 -6 ) (13+

5356 ×57

83 ×(13 -8821 ×16 )

13 +4217 +3 +7

2125619 )×913 517 +517 ×16 910 ×11-910 435 ×8 ×59 1011

6126613 ×12+66

13 65 ×215 +24

15 ÷5 57 ×14 +34 ×57×11

7 -7

6122316161

×48 ×34×7× × + × 477356115 32535

53575 352056 17251792185335 1101125 37747878 5951245912 2

2517

1592545 2215514

79192919633762

1613931326 ÷+÷  

3737

231456

1152812

45134547

815 ×3114 -6 ÷ 2

458511824 813717513 56214731654 ×56 +156 ×4 32.63

5204813717613

124144 169 +271 )×23+2571×4

5 +32.6×0.2

5124631311 × + ÷6 465× × + ×

767 127 -(517 +2 )

4455 ×7 ×4 -13

38956316 46414 +318 )]÷459 ×6+49 ÷1

6 1187499 4

848418 ×58+18 ×42 180÷2.5÷4 7929310 [1-(

1211223531114  1 1

46471634633

5192737233319  

484832

1103205825 1859498

4104535103 96

4355562825514 215759 -3.2×0.5+0.4 9.65

305305561213910 1525247 ÷(9.6×4)

2.08×(9.6÷2.4)÷4.8 78×0.69+1.2×6.9+6.9 0.78÷0.25×4

731312642351  

356

512×7325×14

1155÷7+5455×7

(81515)3

888879÷1352÷36 (13+1315)÷13 1(11224)]36

491335×859÷8

5857×9÷21×3 2.6×1.9÷2.6×1.9

[

17.64÷4.9+6.73 3.4÷[(1.2+0.5)×5] 0.25×12.5×3.2

155 1634 712312 666

(31.4)815

4579+3759

878889 2.65

551.252130.82 (17-12)14 ×1.7+1.35×1.7 23.47

81181112(5554-6)3

115(13+112) ÷7.8-2.1

0.75×18÷0.15 2.5×3.2×1.25 2842÷14+74×3

4134132+-+ 5.2-11÷7-×3 4÷1+6×

357575733632511111×4÷4× ÷[(-)÷] 1+++++ 4454362481632

7.6×÷[1.9-1.9×(1.9-1.9)] (5 -1.8)÷[(1.15+ )×1 ]

14

8

1225132023

327 -6.46-3.54 4.2÷1.5-1.5×0.6 (0.92+ )÷(4-2 ) 17259

533224 (4 -3 )÷( + ) 51.6÷[(3 -1.25)× ]

6414755

19.98×37-199.8×1.9+1998×0.82 9999×7+1111×37

231÷2312311232 (70+168)×69 8.89

1-1÷2-1÷3-16 2007×20052006

1.65÷5+1.29×0.2+350×20% (

9

×36+8.89×63+8.89

×113(13 -

24215+112)×3+35

216

3113714×[-(-)] 24×(-)÷ 4.85×0.17+0.485×8.3 98654164

21634511+×99+ 2-2.86×(6.25-6) 54.2- +4.8- 14714

0.7÷[(51

6 -4 )×24]

78÷9×3355÷72

25×1115+25÷154 [(

64÷(2-1.02)+0.61×14 200023+(45-23)×53 (45-14)×6911]÷20 (10

99÷12.5÷25÷0.8÷4

115+349)×15-45÷49

12+14)÷(415÷4-10)

1.47

7.28-(1.25+0.28) 9990×200.8+1×2008 0.8×4×12.5×2.5

121123 ÷[( + )× ] 4×0.6+0.6÷ 33.02-(148.4-90.85)÷2.5 53513

(1÷27+27÷1)÷5.1

[1-(15+3110)]÷8 56 1212÷[3×(6+13)]

3141.6×58+3.6÷344)×29×(4537+8-4) 213+3×34 11

35×7.27+2.73×35

(56-34)÷(14+16)

521511×[(53)÷6]

( 5411251124.85- +5.15- + ×( - ) 5×(+ )×17

991313231517

34136621417 ÷[( +)× ]  - ×( + ) 4547

5794719

10.2-(1.25 + 2.5)÷1.5 1

1116 ×40-91

16 ÷40

5315723563438 18 ÷(14 + 2.5×45 ) 34×(

117+113)×13 12

739711257110

67 - 67 ×( 21

3 + 9[1-(12-124)]×

3

) (-×

253457872451)÷ ÷[(-)×3] (8×+÷)×12.5

22156399851131115121 +× ÷[(+)×] (+-)÷

963 1920×17-35÷7 8.24

2219.050.812.5

2577191597

512206-2.4÷2.5÷0.4 24.8105124.8512 709284291716 13

84540-155316÷7÷4 7583246112435

321583.6 1.56

41315211 4452 75.8675.878.53 136

5455

412120.75115

118(142.545) 6.75 223554 25333648

778.884378.817 -1156+3.25-26 91481415171715 727115110 14

234793591.625238

12÷[2113×(6+3)]

12315113710 (11129318)×36 11921516143524÷[-(+)]   81054 19385265511

38 ×4÷38 ×4

(412-3310)×(4-213) 17

25×1115+25÷154

87111235325 5843+5384 ×[(1113+1.5)÷14] 738÷9×5÷3572 15

8635152 ÷ 4 × 23

58 ÷ 712 ÷ 710 3.3[383135(140.15)]23+(4255-3)×3

[( 6934111411-)×]÷ (+)÷(÷4-) (+)×15-45÷49

112054245101549111111111++++++++ 2612203042 1255×(6+12)+0.8 11

839[4(237168)]

56×(29÷56+ 56)

(0.92+2725 )÷(4-2 9 ) 567290÷〔611×(34+16)〕 920 ÷ [ 12 ×(25 + 45 )]

(13445)815 521511×[(53)÷6]

51.6÷[(3 25 -1.25)×45 ] (5 25 -1.8)÷[(1.15+132

20 )×1 3

]

16

(41771121 + )÷ + [1-( - )]× 3.64×[1÷(2 -2.09)] 5431024310

(2512 +158 +2712 +3. 375

7150.24-2270.875

(21555+3)÷6×11

(13+34)×24

)×320 19 +18 ÷ 384 +9 2135.432312334938×〔89÷(56-34)〕 0.5+596×(0.15+20) 17

13 +0.2)×7

8 ÷(3—0.5) 25(1563310) 31115÷[(12+20)×6]

( 5

432×3.8+5.2×80%+0.8 (-)×12÷0.1 543

1111111111 + + +……+ + + 1×33×55×717×1919×211223344556

11×2×3 +12×3×4 +11

3×4×5 +……+48×49×50

二、解方程。

45815 416921

2389 X×(1-14 )=3.6

34 ×(X-13 )=0 5X-3×1077 =5 5

18

2334

12 -415 X=10

-23 X= 1

3

114192 5×(X- )=2  1

3

χ×(1+14 )=250

χ×(1-114 -5 )=550 10

X×13×35=4 X

3.2×4+50x=112.8 0.3x

432χ-25 χ=0.3 ×X=825 33×35=18×14 -0.8×60=72 5.9x19

51537 χ+119

4 χ=5

÷X=1120

113χ+6χ=9.5

-2.4x=7

5×1.3-2x=5.5 5x-2+1.8=3.6 7(x-1.2)=2.1

3.2×4+50x=112.8 0.3x

5×1.3-2x=5.5 0.8

34χ+56χ-6=13 1

4×(x-0.8)=8

x-0.15x=8.5 0.8

-0.8×60=725.9 x×(7.2+х)=7.92 6.2-23=35 414 ÷x=2

3

(6+3x)×(x-0.4)=8 20

-2.4x=7 х-х=41.6 -7×1.3=9.9

÷2=18

12 x + 1

3

x=15

311316x-6.4x=36 xx x- x =3

1-34=35 510x7x63.9 21

555x41187

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