mm 仅需
Nt2=Nt1*y2/y1+(1-y2/y1)N/n=23.50Nt5=Nt1*y5/y1+(1-y5/y1)N/n=0.00Nt3=Nt1*y3/y1+(1-y3/y1)N/n=0.00Nt6=Nt1*y6/y1+(1-y6/y1)N/n=0.00Nt1‘=2N/n-Nt1=-70.50Nt4‘=2N/n-Nt4=0.00Nt2‘=2N/n-Nt2=-23.50Nt5’=2N/n-Nt5=0.00Nt3’=2N/n-Nt3=0.00Nt6‘=2N/n-Nt6=0.000.8P=152N/n=0 β0.9nfμ(P-1.25Nt1)=Nvb1=50.43KN ∑Nvbi=β0.9nfμ∑(P-1.25Nti)=636.08KN Nv1=29.375KN
1.1-(h+2ef)/150d。=β=1.00 计算结果
Nt1<0.8P结论0满足要求 Nvb1>Nv1结论1满足要求 ∑Nvbi t≥√6efNt/bf=0mm00mmmm√6efewNt/[ewb+2ef(ef+ew)]f=√12efewNt/[ewb+4ef(ef+ew)]f= 端板设置螺栓处构件腹板强度验算 0.4P=76 Nt2≤0.4P 满足要求0.4P/ewtw=190 因篇幅问题不能全部显示,请点此查看更多更全内容